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7x^2-2+5x-4x^2-17=0
We add all the numbers together, and all the variables
3x^2+5x-19=0
a = 3; b = 5; c = -19;
Δ = b2-4ac
Δ = 52-4·3·(-19)
Δ = 253
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{253}}{2*3}=\frac{-5-\sqrt{253}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{253}}{2*3}=\frac{-5+\sqrt{253}}{6} $
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